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JEE Mains · Physics · STD 12 - Wave optics
  • JEE Mains 2022
  • Medium
  • Numerical

The two light beams having intensities I and 9I interfere to produce a fringe pattern on a screen. The phase difference between the beams is \(\frac{\pi}{2}\) at point \(P\) and \(\pi\) at point \(Q\). Then the difference between the resultant intensities at \(P\) and \(Q\) will be.......\(I\)

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Answer & Solution

Correct Answer

(B) \(6\)

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Detailed explanation

\(I _{ P }= I +9 I +2 \sqrt{ I \times 9 I } \cos \frac{\pi}{2}\)

\(I _{ P }=10\, I\)

\(I _{ Q }= I +9 I +2 \sqrt{ I \times 9 I } \cos \pi\)

\(=10 I -6 I =4 I\)

\(\therefore I _{ P }- I _{ Q }=10 I -4 I =6 I\)

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