ExamBro
ExamBro
JEE Mains · Physics · STD 11 - Work,energy,power and collision
  • JEE Mains 2021
  • Medium
  • Numerical

If the kinetic energy of a moving body becomes four times its initial kinetic energy, then the percentage change in its momentum will be \(...\%\)

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(A) \(100\)

Step-by-step Solution

Detailed explanation

\({K}_{2}=4 {K}_{1}\)

\(\frac{1}{2} m v_{2}^{2}=4 \frac{1}{2} m v_{1}^{2}\)

\(v_{2}=2 v_{1}\)

\(P=m v\)

\(P_{2}=m v_{2}=2 m v_{1}\)

\(P_{1}=m v_{1}\)

\(\% \,\text { change }=\frac{\Delta P}{P_{1}} \times 100=\frac{2 m v_{1}-m v_{1}}{m v_{1}} \times 100=100\, \%\)

Same subject
Explore more questions on app