JEE Mains · Physics · STD 12 -7. Alternating current
An alternating current is represented by the equation, \(i=100 \sqrt{2} \sin (100 \pi t)\) ampere. The RMS value of current and the frequency of the given alternating current are ________.
- A \(100 \sqrt{2} \mathrm{~A}, 100 \mathrm{~Hz}\)
- B \(\frac{100}{\sqrt{2}} \mathrm{~A}, 100 \mathrm{~Hz}\)
- C \(100 \mathrm{~A}, 50 \mathrm{~Hz}\)
- D \(50 \sqrt{2} \mathrm{~A}, 50 \mathrm{~Hz}\)
Answer & Solution
Correct Answer
(C) \(100 \mathrm{~A}, 50 \mathrm{~Hz}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{i}_{\mathrm{r}}=\frac{\mathrm{i}_0}{\sqrt{2}}=100 \mathrm{~A} \\ & \mathrm{f}=\frac{\mathrm{w}}{2 \pi}=\frac{100 \pi}{2 \pi}=50 \mathrm{~Hz}\end{aligned}\)
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