JEE Mains · Physics · STD 12 - 10. Wave optics
In a Young's double slit experiment, a laser light of \(560\,nm\) produces an interference pattern with consecutive bright fringes' separation of \(7.2\,mm\). Now another light is used to produce an interference pattern with consecutive bright fringes' separation of \(8.1\,mm\). The wavelength of second light is \(......nm\)
- A \(600\)
- B \(620\)
- C \(630\)
- D \(645\)
Answer & Solution
Correct Answer
(C) \(630\)
Step-by-step Solution
Detailed explanation
\(\beta \propto \lambda\) \(\lambda_{2}=\frac{9}{8} \lambda_{1}\) \(\therefore \beta_{2}=\frac{9}{8} \beta_{1}=\frac{9}{8} \times 560=630\,nm\)
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