JEE Mains · Physics · STD 12 - 9. Ray optics and optical instruments
The difference of speed of light in the two media \(A\) and \(B\,\left(v_{A}-v_{B}\right)\) is \(2.6 \times 10^{7}\,m / s\). If the refractive index of medium \(B\) is \(1.47\), then the ratio of refractive index of medium \(B\) to medium \(A\) is: (Given : speed of light in vacuum \(\left.c =3 \times 10^{8}\, ms ^{-1}\right)\)
- A \(1.303\)
- B \(1.318\)
- C \(1.13\)
- D \(0.12\)
Answer & Solution
Correct Answer
(C) \(1.13\)
Step-by-step Solution
Detailed explanation
\(v =\frac{ c }{\mu}\) \(\Rightarrow v _{ B }=\frac{3 \times 10^{8}}{1.47}=2.04 \times 10^{8}=20.4 \times 10^{7} m / s\) \(\because v _{ A }- v _{ B }=2.6 \times 10^{7} m / s\) \(\therefore v _{ A }=(20.4+2.6) \times 10^{7}=23 \times 10^{7} m / s\)…
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