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JEE Mains · Physics · STD 12 - Ray optics and optical instruments
  • JEE Mains 2022
  • Hard
  • MCQ

The difference of speed of light in the two media \(A\) and \(B\,\left(v_{A}-v_{B}\right)\) is \(2.6 \times 10^{7}\,m / s\). If the refractive index of medium \(B\) is \(1.47\), then the ratio of refractive index of medium \(B\) to medium \(A\) is: (Given : speed of light in vacuum \(\left.c =3 \times 10^{8}\, ms ^{-1}\right)\)

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Answer & Solution

Correct Answer

(C) \(1.13\)

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Detailed explanation

\(v =\frac{ c }{\mu}\)

\(\Rightarrow v _{ B }=\frac{3 \times 10^{8}}{1.47}=2.04 \times 10^{8}=20.4 \times 10^{7} m / s\)

\(\because v _{ A }- v _{ B }=2.6 \times 10^{7} m / s\)

\(\therefore v _{ A }=(20.4+2.6) \times 10^{7}=23 \times 10^{7} m / s\)

\(\therefore \frac{\mu_{ B }}{\mu_{A}}=\frac{ v _{ A }}{ v _{ B }}=\frac{23 \times 10^{7}}{20.4 \times 10^{7}}=1.13\)

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