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JEE Mains · Physics · STD 12 - Semicondutor electronics
  • JEE Mains 2021
  • Medium
  • Numerical

For the circuit shown below, calculate the value of \({I}_{{z}}\) : (In \({mA}\))

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Answer & Solution

Correct Answer

(D) \(25\)

Step-by-step Solution

Detailed explanation

\(I=\frac{50}{1000}=50\, {mA}\)

\({R}=1000 \,\Omega\)

\(I=\frac{50}{2000}=25\, m A\)

\(I_{z}=I_{1000}-I_{2000}\)

\(=50-25=25\, {mA}\)

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