JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
For the circuit shown below, calculate the value of \({I}_{{z}}\) : (In \({mA}\))
- A \(0.15\)
- B \(0.05\)
- C \(0.1\)
- D \(25\)
Answer & Solution
Correct Answer
(D) \(25\)
Step-by-step Solution
Detailed explanation
\(I=\frac{50}{1000}=50\, {mA}\) \({R}=1000 \,\Omega\) \(I=\frac{50}{2000}=25\, m A\) \(I_{z}=I_{1000}-I_{2000}\) \(=50-25=25\, {mA}\)
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