One end of a straight uniform \(1\; \mathrm{m}\) long bar is pivoted on horizontal table. It is released from rest when it makes an angle \(30^{\circ}\) from the horizontal (see figure). Its angular speed when it hits the table is given as \(\sqrt{\mathrm{n}}\; \mathrm{s}^{-1},\) where \(\mathrm{n}\) is an integer. The value of \(n\) is

\(\mathrm{U}_{\mathrm{i}}+\mathrm{K}_{\mathrm{i}}=\mathrm{U}_{\mathrm{f}}+\mathrm{K}_{\mathrm{r}}\)

\(\Rightarrow \mathrm{mg} \frac{\ell}{2} \sin 30^{\circ}+0=0+\frac{1}{2} \mathrm{I} \omega^{2}\)

\(\Rightarrow \operatorname{mg} \times \frac{1}{2} \times \frac{1}{2}+0=0+\frac{1}{2} \times \frac{\mathrm{m}(1)^{2}}{3} \omega^{2}\)

\(\Rightarrow \omega^{2}=\frac{3 \mathrm{g}}{2} \Rightarrow \omega=\sqrt{15}\)

\(\therefore n=15\)