JEE Mains · Physics · STD 12 - 12. atoms
The angular momentum for the electron in Bohr's orbit is \(L\). If the electron is assumed to revolve in second orbit of hydrogen atom, then the change in angular momentum will be
- A \(\frac{L}{2}\)
- B \(0\)
- C \(L\)
- D \(2L\)
Answer & Solution
Correct Answer
(C) \(L\)
Step-by-step Solution
Detailed explanation
\(L = mvr , \quad r \propto n ^2, \quad v \propto \frac{1}{ n }\) \(\therefore L \propto n\) \(\text { Also, } L =\frac{ nh }{2 \pi}, \text { Bohr orbit is, } L _1= L =\frac{1 . h }{2 \pi}\) \(L _2=2[ L ]=2 L\) \(L _2=\frac{2 h }{2 \pi}\) So, change \(= L _2- L _1=2 L - L = L\)
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