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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2014
  • Medium
  • MCQ

In a large building, there are \(15\) bulbs of \(40\ W\), \(5\) bulbs of \(100\ W, 5\) fans of \(80\ W\) and \(1\) heater of \(1\ kW\). The voltage of electric mains is \(220\ V\). The minimum capacity of the main fuse of the building will be ................ \(A\)

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Answer & Solution

Correct Answer

(B) \(12\) 

Step-by-step Solution

Detailed explanation

Total power consumed by electrical appliances in the building, \(P_{\text {total }}=2500\, \mathrm{W}\)

Watt \(=\) Volt \(\times\) ampere

\(\Rightarrow \quad 2500=\mathrm{V} \times \mathrm{I}\)

\(\Rightarrow \quad 2500=2201\)

\(\Rightarrow \quad I=\frac{2500}{220}=11.36 \approx 12\, \mathrm{A}\)

(Minimum capacity of main fuse)

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