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JEE Mains · Physics · STD 12 - Ray optics and optical instruments
  • JEE Mains 2024
  • Hard
  • Numerical

The distance between object and its \(3\) times magnified virtual image as produced by a convex lens is \(20 \mathrm{~cm}\). The focal length of the lens used is _______ \(\mathrm{cm}\).

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Answer & Solution

Correct Answer

(C) \(15\)

Step-by-step Solution

Detailed explanation

\(\mathrm{v}=3 \mathrm{u}\)

\(\mathrm{v}-\mathrm{u}=20 \mathrm{~cm}\)

\(2 \mathrm{u}=20 \mathrm{~cm}\)

\(\mathrm{u}=10 \mathrm{~cm}\)

\(\frac{1}{(-30)}-\frac{1}{(-10)}=\frac{1}{\mathrm{f}}\)

\(\mathrm{f}=15 \mathrm{~cm}\)

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