JEE Mains · Physics · STD 12 - Ray optics and optical instruments
- JEE Mains 2024
- Hard
- Numerical
The distance between object and its \(3\) times magnified virtual image as produced by a convex lens is \(20 \mathrm{~cm}\). The focal length of the lens used is _______ \(\mathrm{cm}\).
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(15\)
Step-by-step Solution
Detailed explanation
\(\mathrm{v}=3 \mathrm{u}\)
\(\mathrm{v}-\mathrm{u}=20 \mathrm{~cm}\)
\(2 \mathrm{u}=20 \mathrm{~cm}\)
\(\mathrm{u}=10 \mathrm{~cm}\)
\(\frac{1}{(-30)}-\frac{1}{(-10)}=\frac{1}{\mathrm{f}}\)
\(\mathrm{f}=15 \mathrm{~cm}\)
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