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JEE Mains · Physics · STD 11 - Newtons laws of motion
  • JEE Mains 2021
  • Medium
  • Numerical

The initial mass of a rocket is \(1000\, {kg} .\) Calculate at what rate the fuel (In \({kg} {s}^{-1}\)) should be burnt so that the rocket is given an acceleration of \(20 \,{ms}^{-2}\). The gases come out at a relative speed of \(500\, {ms}^{-1}\) with respect to the rocket : [Use \( g = 10\, {m} / {s}^{2}\) ]

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Answer & Solution

Correct Answer

(D) \(60\)

Step-by-step Solution

Detailed explanation

\(F_{\text {thrust }}=\left(\frac{{dm}}{{dt}} \cdot {V}_{{rel}}\right)\)

\(\left(\frac{{dm}}{{dt}} {V}_{{rel}}-{mg}\right)={ma}\)

\(\Rightarrow\left(\frac{{dm}}{{dt}}\right) \times 500-10^{3} \times 10=10^{3} \times 20\)

\(\frac{{d} {m}}{{dt}}=(60 \,{kg} / {s})\)

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