JEE Mains · Physics · STD 11 - 5. work,energy,power and collision
Two persons \(A\) and \(B\) perform same amount of work in moving a body through a certain distance \({d}\) with application of forces acting at angle \(45^{\circ}\) and \(60^{\circ}\) with the direction of displacement respectively. The ratio of force applied by person \(A\) to the force applied by person \(B\) is \(\frac{1}{\sqrt{x}}\). The value of \(x\) is ...... .
- A \(2\)
- B \(3\)
- C \(1\)
- D \(4\)
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
\(\text { Given } {W}_{{A}}={W}_{{B}}\) \({F}_{{A}} {d} \cos 45^{\circ}={F}_{{B}} {d} \cos 60^{\circ}\) \({F}_{A} \times \frac{1}{\sqrt{2}}={F}_{{B}} \times \frac{1}{2}\) \(\frac{{F}_{{A}}}{{F}_{{B}}}=\frac{\sqrt{2}}{2}=\frac{1}{\sqrt{2}}\) \({x}=2\)
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