ExamBro
ExamBro
JEE Mains · Physics · STD 11 - 13. oscillations

The displacement of a damped harmonic oscillator is given by \(x\left( t \right) = {e^{ - 0.1\,t}}\,\cos \left( {10\pi t + \varphi } \right)\)  The time taken for its amplitude of vibration to drop to half of its initial value is close to .... \(s\)

  1. A \(13\)
  2. B \(27\)
  3. C \(4\)
  4. D \(7\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(7\)

Step-by-step Solution

Detailed explanation

\(A=A_{0} e^{-0.1 t}=\frac{A_{0}}{2}\) \(\ln 2=0.1 \mathrm{t}\) \(t=10\, \mathrm{ln} 2=6.93 \approx 7 \mathrm{sec}\)
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app