JEE Mains · Physics · STD 11 - Work,energy,power and collision
- JEE Mains 2021
- Hard
- Numerical
A ball of mass \(10\, kg\) moving with a velocity \(10 \sqrt{3}\, ms ^{-1}\) along \(X-\)axis, hits another ball of mass \(20\, kg\) which is at rest. After collision, the first ball comes to rest and the second one disintegrates into two equal pieces. One of the pieces starts moving along \(Y-\) axis at a speed of \(10\, m / s\). The second piece starts moving at a speed of \(20\, m / s\) at an angle \(\theta\) (degree) with respect to the \(X-\)axis. The configuration of pieces after collision is shown in the figure. The value of \(\theta\) to the nearest integer is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(30\)
Step-by-step Solution
Detailed explanation
From conservation of momentum along \(x\) axis
\(\overrightarrow{ P }_{ i }=\overrightarrow{ P }_{ f }\)
\(10 \times 10 \sqrt{3}=200 \cos \theta\)
\(\cos \theta=\frac{\sqrt{3}}{2}\)
\(\theta=30^{\circ}\)
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