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JEE Mains · Physics · STD 11- 8. mechanical properties of solids

The depth below the surface of sea to which a rubber ball be taken so as to decrease its volume by \(0.02 \%\) is ______ \(\mathrm{m}\). (Take density of sea water \(=10^3 \mathrm{kgm}^{-3}\), Bulk modulus of rubber \(=9 \times 10^8 \mathrm{Nm}^{-2}\), and \(\mathrm{g}=10 \mathrm{~ms}^{-2}\) )

  1. A \(15\)
  2. B \(16\)
  3. C \(17\)
  4. D \(18\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(18\)

Step-by-step Solution

Detailed explanation

\(\beta=\frac{-\Delta \mathrm{P}}{\frac{\Delta \mathrm{V}}{\mathrm{V}}}\) \(\Delta \mathrm{P}=-\beta \frac{\Delta \mathrm{V}}{\mathrm{V}}\) \(\rho \mathrm{gh}=-\beta \frac{\Delta \mathrm{V}}{\mathrm{V}}\)…
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