JEE Mains · Physics · STD 12 - Atoms
- JEE Mains 2017
- Medium
- MCQ
Some energy levels of a molecule are shown in the figure. The ratio of the wavelengths \(r\) =\(\frac{{{\lambda _1}}}{{{\lambda _2}}}\) is given by

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Answer & Solution
Correct Answer
(D) \(\;r = \frac{1}{3}\)
Step-by-step Solution
Detailed explanation
From energy level diagram, using \(\Delta E=\frac{h c}{\lambda}\)
For wavelength \(\lambda_{1} \Delta E=-E-(-2 E)=\frac{h c}{\lambda_{1}}\)
\(\therefore \quad \lambda_{1}=\frac{h c}{E}\)
For wavelength \(\lambda_{2} \Delta E=-E-\left(-\frac{4 E}{3}\right)=\frac{h c}{\lambda_{2}}\)
\(\therefore \quad {\lambda _2} = \frac{{hc}}{{\left( {\frac{E}{3}} \right)}}\) \(\therefore r = \frac{{{\lambda _1}}}{{{\lambda _2}}} = \frac{1}{3}\)
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