JEE Mains · Physics · STD 12 - 12. atoms
Some energy levels of a molecule are shown in the figure. The ratio of the wavelengths \(r\) =\(\frac{{{\lambda _1}}}{{{\lambda _2}}}\) is given by
- A \(r = \frac{4}{3}\)
- B \(\;r = \frac{2}{3}\)
- C \(\;r = \frac{3}{4}\)
- D \(\;r = \frac{1}{3}\)
Answer & Solution
Correct Answer
(D) \(\;r = \frac{1}{3}\)
Step-by-step Solution
Detailed explanation
From energy level diagram, using \(\Delta E=\frac{h c}{\lambda}\) For wavelength \(\lambda_{1} \Delta E=-E-(-2 E)=\frac{h c}{\lambda_{1}}\) \(\therefore \quad \lambda_{1}=\frac{h c}{E}\) For wavelength…
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