JEE Mains · Physics · STD 12 - 12. atoms
According to Bohr's theory, the time averaged magnetic field at the centre (i.e. nucleus) of a hydrogen atom due to the motion of electrons in the \(n^{th}\) orbit is proportional to (\(n =\) principal quantum number)
- A \(n^{-4}\)
- B \(n^{-5}\)
- C \(n^{-3}\)
- D \(n^{-2}\)
Answer & Solution
Correct Answer
(D) \(n^{-2}\)
Step-by-step Solution
Detailed explanation
Magnetic field at the centre of nucleus of \(\mathrm{H}\) -atom, \(\mathrm{B}=\frac{\mu_{0} \mathrm{I}}{2 \mathrm{r}}\) ..... \((i)\) According to Bohr's model, radius of orbit \(r\, \propto \,{n^2}\) from eq. \((i)\) we can also write as \(B \propto n^{-2}\)
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