JEE Mains · Physics · STD 11 - Oscillations
- JEE Mains 2021
- Hard
- Numerical
In the reported figure, two bodies \(A\) and \(B\) of masses \(200\, {g}\) and \(800\, {g}\) are attached with the system of springs. Springs are kept in a stretched position with some extension when the system is released. The horizontal surface is assumed to be frictionless. The angular frequency will be \(.....\,{rad} / {s}\) when \({k}=20 \,{N} / {m} .\)

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Answer & Solution
Correct Answer
(C) \(10\)
Step-by-step Solution
Detailed explanation
\(\omega=\sqrt{\frac{k_{\text {eq }}}{\mu}}\)
\(\mu=\) reduced mass
springs are in series connection
\(k _{eq}=\frac{ k _{1} k _{2}}{ k _{1}+ k _{2}}\)
\(k _{ eq }=\frac{ k \times 4 k }{5 k }=\frac{4 k }{5}\)
\(k _{ eq }=\frac{4 \times 20}{5} N / m =16 N / m\)
\(\mu=\frac{ m _{1} m _{2}}{ m _{1}+ m _{2}}=\frac{0.2 \times 0.8}{0.2+0.8}=0.16 kg\)
\(\omega=\sqrt{\frac{16}{0.16}}=\sqrt{100}=10\)
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