JEE Mains · Physics · STD 12 - 12. atoms
The acceleration of an electron in the first orbit of the hydrogen atom \((z\, = 1)\) is
- A \(\frac{{{h^2}}}{{{\pi ^2}{m^2}{r^3}}}\)
- B \(\frac{{{h^2}}}{{8{\pi ^2}{m^2}{r^3}}}\)
- C \(\frac{{{h^2}}}{{4{\pi ^2}{m^2}{r^3}}}\)
- D \(\frac{{{h^2}}}{{4\pi {m^2}{r^3}}}\)
Answer & Solution
Correct Answer
(C) \(\frac{{{h^2}}}{{4{\pi ^2}{m^2}{r^3}}}\)
Step-by-step Solution
Detailed explanation
Speed of electron in first orbit \((\mathrm{n}=1)\) of hydrogen atom \((z=1)\), \(v = \frac{{{e^2}}}{{2{\varepsilon _0}h}}\) radius of Bohr's first orbit, \(r=\frac{h^{2} \varepsilon_{0}}{\pi m e^{2}} \Rightarrow \varepsilon_{0}=\frac{r \pi m \mathrm{e}^{2}}{h^{2}}\) .....…
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