JEE Mains · Physics · STD 11 - 10.2 transmission of heat
A bowl filled with very hot soup cools from \(98^{\circ}\,C\) to \(86^{\circ}\,C\) in \(2\) minutes when the room temperature is \(22^{\circ}\,C\). \(..........\,minutes\) long it will take to cool from \(75^{\circ}\,C\) to \(69^{\circ}\,C\) ?
- A \(2\)
- B \(1.4\)
- C \(0.5\)
- D \(1\)
Answer & Solution
Correct Answer
(B) \(1.4\)
Step-by-step Solution
Detailed explanation
\(\frac{\Delta Q }{\Delta t }=- K \left( T - T _0\right)\) \(\frac{\Delta Q }{\Delta t }=- K \left( T _{ avg }- T _0\right)\) \((i)\) \(\frac{ ms \times 12}{2}=- K \left(\frac{98+86}{2}-22\right)\) \(6=-\frac{ K }{ ms }\left[\frac{98+86}{2}-22\right]\)…
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