JEE Mains · Physics · STD 12 - Dual nature of radiation and matter
- JEE Mains 2025
- Easy
- MCQ
A light source of wavelength \(\lambda\) illuminates a metal surface and electrons are ejected with maximum kinetic energy of 2 eV . If the same surface is illuminated by a light source of wavelength \(\frac{\lambda}{2}\), then the maximum kinetic energy of ejected electrons will be (The work function of metal is 1 eV )
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) 5 eV
Step-by-step Solution
Detailed explanation
Einstein's photoelectric equation
\(\begin{aligned}
& \mathrm{KE}=\frac{h c}{\lambda}=\phi_0 \\
& 2 \mathrm{eV}=\frac{h c}{\lambda}-1 \mathrm{eV} \\
& \frac{h c}{\lambda}=3 \mathrm{eV} \\
& \mathrm{KE}^{\prime}=\frac{h c}{(\lambda / 2)}-\phi_0=6 \mathrm{eV}-1 \mathrm{eV}
\end{aligned}\)
\(=5 \mathrm{eV}\)
\(\begin{aligned}
& \mathrm{KE}=\frac{h c}{\lambda}=\phi_0 \\
& 2 \mathrm{eV}=\frac{h c}{\lambda}-1 \mathrm{eV} \\
& \frac{h c}{\lambda}=3 \mathrm{eV} \\
& \mathrm{KE}^{\prime}=\frac{h c}{(\lambda / 2)}-\phi_0=6 \mathrm{eV}-1 \mathrm{eV}
\end{aligned}\)
\(=5 \mathrm{eV}\)
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