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JEE Mains · Physics · STD 12 - Electric charges and fields
  • JEE Mains 2024
  • Hard
  • Numerical

An electric field is given by \((6 \hat{i}+5 \hat{j}+3 \hat{k}) \ N / C\). The electric flux through a surface area \(30 \hat{\mathrm{i}}\; m^2\) lying in \(YZ-\)plane (in SI unit) is _______.

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Answer & Solution

Correct Answer

(C) \(180\)

Step-by-step Solution

Detailed explanation

\( \overrightarrow{\mathrm{E}}=6 \hat{\mathrm{i}}+5 \hat{\mathrm{j}}+3 \hat{\mathrm{k}}\)

\( \overrightarrow{\mathrm{A}}=30 \hat{\mathrm{i}} \)

\( \phi=\overrightarrow{\mathrm{E}} \cdot \overrightarrow{\mathrm{A}} \)

\( \phi=(6 \hat{\mathrm{i}}+5 \hat{\mathrm{j}}+3 \hat{\mathrm{k}}) \cdot(30 \hat{\mathrm{i}}) \)

\( \phi=6 \times 30=180\)

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