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JEE Mains · Physics · STD 12 - Electric potential and capacitance
  • JEE Mains 2019
  • Medium
  • MCQ

A parallel plate capacitor with plates of area \(1\,m^2\) each, are at a separation of \(0.1\,m.\) If the electric field between the plates is \(100\,N/C,\) the magnitude of charge on each plate

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Answer & Solution

Correct Answer

(C) \(8.85\times 10^{-10}\,C\)

Step-by-step Solution

Detailed explanation

\(\mathrm{E}=\frac{\mathrm{q}}{\mathrm{A} \varepsilon_{0}}\)

\(\Rightarrow \quad \mathrm{q}=\mathrm{E} \mathrm{A} \varepsilon_{0}\)

\(\Rightarrow \quad \mathrm{q}=100 \times 1 \times 8.85 \times 10^{-12}\)

\(\Rightarrow \mathrm{q}=8.85 \times 10^{-10}\, \mathrm{C}\)

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