JEE Mains · Physics · STD 11 - 7. gravitation
If the distance of the earth from Sun is \(1.5 \times 10^6\,km\). Then the distance of an imaginary planet from Sun, if its period of revolution is \(2.83\) years is \(.............\times 10^6\,km\)
- A \(0.6\)
- B \(6\)
- C \(3\)
- D \(0.3\)
Answer & Solution
Correct Answer
(C) \(3\)
Step-by-step Solution
Detailed explanation
\(T ^2 \propto R ^3 \Rightarrow\left(\frac{ T _1}{ T _2}\right)^2=\left(\frac{ R _1}{ R _2}\right)^3\) \(\Rightarrow\left(\frac{1}{2.83}\right)^2=\left(\frac{1.5 \times 10^6}{ R _2}\right)^3\)…
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