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JEE Mains · Physics · STD 11 - Gravitation
  • JEE Mains 2023
  • Medium
  • Numerical

If the distance of the earth from Sun is \(1.5 \times 10^6\,km\). Then the distance of an imaginary planet from Sun, if its period of revolution is \(2.83\) years is \(.............\times 10^6\,km\)

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Answer & Solution

Correct Answer

(C) \(3\)

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Detailed explanation

\(T ^2 \propto R ^3 \Rightarrow\left(\frac{ T _1}{ T _2}\right)^2=\left(\frac{ R _1}{ R _2}\right)^3\)

\(\Rightarrow\left(\frac{1}{2.83}\right)^2=\left(\frac{1.5 \times 10^6}{ R _2}\right)^3\)

\(\Rightarrow R _2=\left[(2.83)^2 \times\left(1.5 \times 10^6\right)^3\right]^{1 / 3}\)

\(=8^{1 / 3} \times 1.5 \times 10^6=3 \times 10^6\,km\)

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