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JEE Mains · Physics · STD 11 - Surface tension
  • JEE Mains 2023
  • Medium
  • Numerical

The surface tension of soap solution is \(3.5 \times 10^{-2}\,Nm ^{-1}\). The amount of work done required to increase the radius of soap bubble from \(10\,cm\) to \(20\,cm\) is \(.....\times 10^{-4}\,J\)

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Answer & Solution

Correct Answer

(A) \(264\)

Step-by-step Solution

Detailed explanation

\(W = T .(\Delta A )\)

\(W = T \left(8 \pi\left( r _2^2- r _1^2\right)\right)\)

\(W =264 \times 10^{-4}\,J\)

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