JEE Mains · Physics · STD 11 - Surface tension
- JEE Mains 2023
- Medium
- Numerical
The surface tension of soap solution is \(3.5 \times 10^{-2}\,Nm ^{-1}\). The amount of work done required to increase the radius of soap bubble from \(10\,cm\) to \(20\,cm\) is \(.....\times 10^{-4}\,J\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(264\)
Step-by-step Solution
Detailed explanation
\(W = T .(\Delta A )\)
\(W = T \left(8 \pi\left( r _2^2- r _1^2\right)\right)\)
\(W =264 \times 10^{-4}\,J\)
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