JEE Mains · Physics · STD 11 - 9.2 surface tension
The surface tension of soap solution is \(3.5 \times 10^{-2}\,Nm ^{-1}\). The amount of work done required to increase the radius of soap bubble from \(10\,cm\) to \(20\,cm\) is \(.....\times 10^{-4}\,J\)
- A \(264\)
- B \(263\)
- C \(262\)
- D \(265\)
Answer & Solution
Correct Answer
(A) \(264\)
Step-by-step Solution
Detailed explanation
\(W = T .(\Delta A )\) \(W = T \left(8 \pi\left( r _2^2- r _1^2\right)\right)\) \(W =264 \times 10^{-4}\,J\)
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