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JEE Mains · Physics · STD 11 - Units,dimensions and measurement
  • JEE Mains 2021
  • Medium
  • MCQ

The force is given in terms of time \(t\) and displacement \(x\) by the equation \({F}={A} \cos {Bx}+{C} \sin {Dt}\) The dimensional formula of \(\frac{{AD}}{{B}}\) is -

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Answer & Solution

Correct Answer

(A) \(\left[{ML}^{2} {T}^{-3}\right]\)

Step-by-step Solution

Detailed explanation

\(\theta\) of cos or sin should be dimensionless.

\({[ A ]=\left[ MLT ^{-2}\right] }\)

\({[ B ]=\left[ L ^{-1}\right] }\)

\({[ D ]=\left[ T ^{-1}\right] }\)

\({\left[\frac{ AD }{ B }\right]=\frac{\left[ MLT ^{-2}\right]\left[ T ^{-1}\right]}{\left[ L ^{-1}\right]} }\)

\({\left[\frac{ AD }{ B }\right]=\left[ ML ^{2} T ^{-3}\right] }\)

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