JEE Mains · Physics · STD 11 - Units,dimensions and measurement
- JEE Mains 2021
- Medium
- MCQ
The force is given in terms of time \(t\) and displacement \(x\) by the equation \({F}={A} \cos {Bx}+{C} \sin {Dt}\) The dimensional formula of \(\frac{{AD}}{{B}}\) is -
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(\left[{ML}^{2} {T}^{-3}\right]\)
Step-by-step Solution
Detailed explanation
\(\theta\) of cos or sin should be dimensionless.
\({[ A ]=\left[ MLT ^{-2}\right] }\)
\({[ B ]=\left[ L ^{-1}\right] }\)
\({[ D ]=\left[ T ^{-1}\right] }\)
\({\left[\frac{ AD }{ B }\right]=\frac{\left[ MLT ^{-2}\right]\left[ T ^{-1}\right]}{\left[ L ^{-1}\right]} }\)
\({\left[\frac{ AD }{ B }\right]=\left[ ML ^{2} T ^{-3}\right] }\)
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