JEE Mains · Physics · STD 12 -6. Electromagnetic induction
Primary coil of a transformer is connected to \(220 \mathrm{~V}\) ac. Primary and secondary turns of the transforms are \(100\) and \(10\) respectively. Secondary coil of transformer is connected to two series resistance shown in shown in figure. The output voltage \(\left(\mathrm{V}_0\right)\) is _______.
- A \(7 \mathrm{~V}\)
- B \(15 \mathrm{~V}\)
- C \(44 \mathrm{~V}\)
- D \(22 \mathrm{~V}\)
Answer & Solution
Correct Answer
(A) \(7 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
\( \frac{\varepsilon_1}{\varepsilon_2}=\frac{N_1}{N_2}=\frac{100}{10} \Rightarrow \varepsilon_2=22 \mathrm{~V} \) \( I=\frac{22}{22 \times 10^3}=1 \mathrm{~mA}, V_0=7 \mathrm{~V}\)
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