JEE Mains · Physics · STD 12 -6. Electromagnetic induction
Primary side of a transformer is connected to \(230 \mathrm{~V}, 50 \mathrm{~Hz}\) supply. Turns ratio of primary to secondary winding is \(10: 1\). Load resistance connected to secondary side is \(46\ \Omega\). The power consumed in it is :
- A \(12.5 \mathrm{~W}\)
- B \(10.0 \mathrm{~W}\)
- C \(11.5 \mathrm{~W}\)
- D \(12.0 \mathrm{~W}\)
Answer & Solution
Correct Answer
(C) \(11.5 \mathrm{~W}\)
Step-by-step Solution
Detailed explanation
\( \frac{\mathrm{V}_1}{\mathrm{~V}_2}=\frac{\mathrm{N}_1}{\mathrm{~N}_2} \) \( \frac{230}{\mathrm{~V}_2}=\frac{10}{1} \) \( \mathrm{~V}_2=23 \mathrm{~V}\) Power consumed \(=\frac{\mathrm{V}_2^2}{\mathrm{R}}\) \(=\frac{23 \times 23}{46}=11.5 \mathrm{~W}\)
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