JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
A car moving with a speed of \(54\) km/h takes a turn of radius \(20\) m. A simple pendulum is suspended from the ceiling of the car. Determine the angle made by the string of the pendulum with the vertical during the turning. (Take \(g=10\) m/s\(^2\))
- A \(\tan^{-1}(0.5)\)
- B \(\tan^{-1}(0.75)\)
- C \(\tan^{-1}(1.125)\)
- D \(\tan^{-1}(0.25)\)
Answer & Solution
Correct Answer
(C) \(\tan^{-1}(1.125)\)
Step-by-step Solution
Detailed explanation
Speed of the car, \(v = 54 \times \dfrac{5}{18} = 15\) m/s. In the frame of the car, the pendulum bob experiences a pseudo force (centrifugal force) horizontally outwards and the gravitational force downwards. Let \(T\) be the tension in the string and \(\theta\) be the angle it…
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