JEE Mains · Physics · STD 12 -6. Electromagnetic induction
In a coil, the current changes form \(-2 \mathrm{~A}\) to \(+2 \mathrm{~A}\) in \(0.2 \mathrm{~s}\) and induces an emf of \(0.1 \mathrm{~V}\). The selfinductance of the coil is _______.
- A \(5 \mathrm{mH}\)
- B \(1 \mathrm{mH}\)
- C \(2.5 \mathrm{mH}\)
- D \(4 \mathrm{mH}\)
Answer & Solution
Correct Answer
(A) \(5 \mathrm{mH}\)
Step-by-step Solution
Detailed explanation
\((E m f)_{\text {induced }}=-L \frac{d i}{d t}\) In magnitude form, \(\left|\operatorname{Emf}_{\text {ind }}\right|=\left|(-) L \frac{d i}{d t}\right|\) \(\Rightarrow 0.1=\frac{(\mathrm{L})[+2-(-2)]}{0.2}\) \(\Rightarrow \mathrm{L}=\frac{0.1 \times 0.2}{4}=5 \mathrm{mH}\)
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