JEE Mains · Physics · STD 12 - Electric charges and fields
- JEE Mains 2021
- Medium
- Numerical
A point charge of \(+\,12 \,\mu C\) is at a distance \(6 \,cm\) vertically above the centre of a square of side \(12\, cm\) as shown in figure. The magnitude of the electric flux through the square will be ....... \(\times 10^{3} \,Nm ^{2} / C\)

Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(226\)
Step-by-step Solution
Detailed explanation
From symmetry \(\phi=\frac{1}{6}\left(\frac{ q }{\varepsilon_{0}}\right)\)
\(=\frac{12 \times 10^{-6}}{6 \times 8.85 \times 10^{-12}}\)
\(=225.98 \times 10^{3} \,\frac{ Nm ^{2}}{ s }\)
\(\simeq 226 \times 10^{3} \, \frac{ Nm ^{2}}{ C }\)
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