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JEE Mains · Physics · STD 12 - Electric charges and fields
  • JEE Mains 2021
  • Medium
  • Numerical

A point charge of \(+\,12 \,\mu C\) is at a distance \(6 \,cm\) vertically above the centre of a square of side \(12\, cm\) as shown in figure. The magnitude of the electric flux through the square will be ....... \(\times 10^{3} \,Nm ^{2} / C\)

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Answer & Solution

Correct Answer

(C) \(226\)

Step-by-step Solution

Detailed explanation

From symmetry \(\phi=\frac{1}{6}\left(\frac{ q }{\varepsilon_{0}}\right)\)

\(=\frac{12 \times 10^{-6}}{6 \times 8.85 \times 10^{-12}}\)

\(=225.98 \times 10^{3} \,\frac{ Nm ^{2}}{ s }\)

\(\simeq 226 \times 10^{3} \, \frac{ Nm ^{2}}{ C }\)

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