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JEE Mains · Physics · STD 11 - Fluid mechanics
  • JEE Mains 2019
  • Hard
  • MCQ

Water from a pipe is coming at a rate of \(100\, litres\) per minute. If the radius of the pipe is \(5\, cm\), the Reynolds number for the flow is of the order of : (density of water \(= 1000\, kg/m^3\), coefficient of viscosity of water \(= 1\, mPa\, s\))

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Answer & Solution

Correct Answer

(D) \(10^4\)

Step-by-step Solution

Detailed explanation

Reynolds number\( = \frac{{\rho vd}}{\eta }\)

Volume flow rate\( = v \times \pi {r^2}\)

\(v = \frac{{100 \times {{10}^{ - 3}}}}{{60}} \times \frac{1}{{\pi  \times 25 \times {{10}^{ - 4}}}}\)

\(v = \frac{2}{{3\pi }}m/s\)

Reynolds number \( = \frac{{{{10}^3} \times 2 \times 10 \times {{10}^{ - 2}}}}{{{{10}^{ - 3}} \times 3\pi }} = 2 \times {10^4}\)

\(Order\,{10^4}\)

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