JEE Mains · Physics · STD 11 - 13. oscillations
particle moves with simple harmonic motion in a straight line. In first \(\tau\ s\), after starting from rest it travels a distance \(a\), and in next \(\tau\ s\) it travels \(2a\), in same direction, then
- A time period of oscillations is \(8\tau\)
- B time period of oscillations is \(6\tau\)
- C amplitude of motion is \(4a\)
- D amplitude of motion is \(3a\)
Answer & Solution
Correct Answer
(B) time period of oscillations is \(6\tau\)
Step-by-step Solution
Detailed explanation
In simple harmonic motion, starting from rest, At \(t=0, x=A\) \(x= Acos\omega t\) \(...(i)\) \( When\,\,\, t=\tau, x=A-a\) When \(t=2 \tau, x=A-3 a\) From equation \(( i )\) \(A-a=A \cos \omega \tau\) \(...(ii)\) \(A-3 a=A \cos 2 \omega \tau\) \(...(iii)\) As…
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