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JEE Mains · Physics · STD 11 - Gravitation
  • JEE Mains 2013
  • Medium
  • MCQ

What is the minimum energy required to launch a satellite of mass \(m\) from the surface of a planet of mass \(M\) and radius \(R\) in a circular orbit at an altitude of \(2R\)?

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Answer & Solution

Correct Answer

(B) \(\;\frac{{5GmM}}{{6R}}\)

Step-by-step Solution

Detailed explanation

Applying energy conservation

\(k + \left( { - \frac{{GMm}}{R}} \right) = \frac{1}{2}mv_0^2 + \left( { - \frac{{GMm}}{{R + h}}} \right)\)

\(k - \frac{{GMm}}{R} = \frac{1}{2}m\left( {\frac{{Gm}}{{R + 2R}}} \right) - \frac{{GMm}}{{R + 2R}}\)

\(\therefore k = \frac{{5GMm}}{{6R}}\)

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