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JEE Mains · Physics · STD 12 - Dual nature of radiation and matter
  • JEE Mains 2024
  • Hard
  • MCQ

Given below are two statements: Statement-\(I\): Figure shows the variation of stopping potential with frequency \((v)\) for the two photosensitive materials \(M_1\) and \(M_2\). The slope gives value of \(\frac{h}{e}\), where \(h\) is Planck's constant, \(e\) is the charge of electron. Statement-\(II\): \(M_2\) will emit photoelectrons of greater kinetic energy for the incident radiation having same frequency. In the light of the above statements, choose the most appropriate answer from the options given below.

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(A) Statement-\(I\) is correct and Statement-\(II\) is incorrect.

Step-by-step Solution

Detailed explanation

\(\mathrm{eV}_0=\mathrm{hv}-\phi\)

\(\mathrm{V}_0=\frac{\mathrm{h}}{\mathrm{e}} \mathrm{v}-\frac{\phi}{\mathrm{e}}\)

\(\mathrm{M}_2\) material has higher work function, so statement-\((II)\) is incorrect.

Option \((1)\) is correct.

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