JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter
Given below are two statements: Statement-\(I\): Figure shows the variation of stopping potential with frequency \((v)\) for the two photosensitive materials \(M_1\) and \(M_2\). The slope gives value of \(\frac{h}{e}\), where \(h\) is Planck's constant, \(e\) is the charge of electron. Statement-\(II\): \(M_2\) will emit photoelectrons of greater kinetic energy for the incident radiation having same frequency. In the light of the above statements, choose the most appropriate answer from the options given below.
- A Statement-\(I\) is correct and Statement-\(II\) is incorrect.
- B Statement-\(I\) is incorrect but Statement-\(II\) is correct.
- C Both Statement-\(I\) and Statement-\(II\) are incorrect.
- D Both Statement-\(I\) and Statement-\(II\) are correct.
Answer & Solution
Correct Answer
(A) Statement-\(I\) is correct and Statement-\(II\) is incorrect.
Step-by-step Solution
Detailed explanation
\(\mathrm{eV}_0=\mathrm{hv}-\phi\) \(\mathrm{V}_0=\frac{\mathrm{h}}{\mathrm{e}} \mathrm{v}-\frac{\phi}{\mathrm{e}}\) \(\mathrm{M}_2\) material has higher work function, so statement-\((II)\) is incorrect. Option \((1)\) is correct.
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