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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2019
  • Medium
  • MCQ

Drift speed of electrons, when \(1.5\, A\) of current flows in a copper wire of cross section \(5\, mm^2\), is \(v\). If the electron density in copper is \(9 \times 10^{28}\, m^3\) the value of \(v\) in \(mm/s\) is close to (Take charge of electron to be \(= 1.6 \times 10^{-19}\, C\))

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Answer & Solution

Correct Answer

(A) \(0.02\)

Step-by-step Solution

Detailed explanation

\(\mathrm{i}=\mathrm{ne} \mathrm{AV}_{\mathrm{d}}\)

\(1.5=9 \times 10^{28} \times 1.6 \times 10^{-19} \times 5 \times \mathrm{Vd}\)

\(\mathrm{Vd}=0.02\)

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