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JEE Mains · Physics · STD 12 - 12. atoms
In the Bohr model an electron moves in a circular orbit around the proton . Considering the orbiting electron to be a circular current loop, the magnetic moment of the hydrogen atom; when the electron is in \(n^{th}\) excited state, is
- A \(\left( {\frac{e}{{2m}}\frac{{{n^2}h}}{{2\pi }}} \right)\)
- B \(\left( {\frac{e}{{m}}} \right)\frac{{nh}}{{2\pi }}\)
- C \(\left( {\frac{e}{{2m}}} \right)\frac{{nh}}{{2\pi }}\)
- D \(\left( {\frac{e}{m}} \right)\frac{{{n^2}h}}{{2\pi }}\)
Answer & Solution
Correct Answer
(C) \(\left( {\frac{e}{{2m}}} \right)\frac{{nh}}{{2\pi }}\)
Step-by-step Solution
Detailed explanation
Magnetic moment of the hydrogen atom, when the electron is in \(\mathrm{n}^{\text {th }}\) excited state, i.e., \(n^{\prime}=(n+1)\) As magnetic moment…
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