JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
The charge on capacitor of capacitance \(15 \mu F\) in the figure given below is \(\dots \; \mu c\)
- A \(60\)
- B \(130\)
- C \(260\)
- D \(585\)
Answer & Solution
Correct Answer
(A) \(60\)
Step-by-step Solution
Detailed explanation
\(\frac{1}{ C _{ eq }}=\frac{1}{10}+\frac{1}{15}+\frac{1}{20}=\frac{12+8+6}{120}=\frac{26}{120}\) \(C _{ eq }=\frac{60}{13} \,\mu F\) \(Q =\frac{13 \times 60}{13}=60 \,\mu C\) Charge on each capacitor is same \(\because\) they are in series.
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