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JEE Mains · Physics · STD 11 - Kinetic theory of gases
- JEE Mains 2013
- Medium
- Numerical
In the isothermal expansion of \(10\,g\) of gas from volume \(V\) to \(2V\) the work done by the gas is \(575\,J\). What is the root mean square speed of the molecules of the gas at that temperature ..... \(m/s\)?
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(499\)
Step-by-step Solution
Detailed explanation
\({v_{rms}} = \sqrt {\frac{{3PV}}{{{\rm{mass\, of\, the\, gas}}}}} \)
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