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JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism

A deuteron and a proton moving with equal kinetic energy enter into to a uniform magnetic field at right angle to the field. If \(r_{d}\) and \(r_{p}\) are the radii of their circular paths respectively, then the ratio \(\frac{r_{d}}{r_{p}}\) will be \(\sqrt{ x }: 1\) where \(x\) is ..........

  1. A \(2\)
  2. B \(3\)
  3. C \(4\)
  4. D \(5\)
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Answer & Solution

Correct Answer

(A) \(2\)

Step-by-step Solution

Detailed explanation

\(R =\frac{ mv }{ q _{ B }}\) \(R _{ D }=\frac{\left(2 m _{ p }\right) v _{ D }}{ e B}\) \(R _{ p }=\frac{\left( m _{ p }\right) v _{ p }}{ e B }\) \(\frac{ R _{ D }}{ R _{ p }}=\frac{2 v _{ D }}{ v _{ p }}=\frac{2 v _{ D }}{\sqrt{2} v _{ D }}=\frac{\sqrt{2}}{1}\)…
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