JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
A deuteron and a proton moving with equal kinetic energy enter into to a uniform magnetic field at right angle to the field. If \(r_{d}\) and \(r_{p}\) are the radii of their circular paths respectively, then the ratio \(\frac{r_{d}}{r_{p}}\) will be \(\sqrt{ x }: 1\) where \(x\) is ..........
- A \(2\)
- B \(3\)
- C \(4\)
- D \(5\)
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
\(R =\frac{ mv }{ q _{ B }}\) \(R _{ D }=\frac{\left(2 m _{ p }\right) v _{ D }}{ e B}\) \(R _{ p }=\frac{\left( m _{ p }\right) v _{ p }}{ e B }\) \(\frac{ R _{ D }}{ R _{ p }}=\frac{2 v _{ D }}{ v _{ p }}=\frac{2 v _{ D }}{\sqrt{2} v _{ D }}=\frac{\sqrt{2}}{1}\)…
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