JEE Mains · Physics · STD 11 - 14. waves and sound
A wire of length \(2\,L\) is made by joining two wires \(A\) and \(B\) of same lengths but different radii \(r\) and \(2r\) and made of the same material. It is vibrating at a frequency such that the joint of the two wires forms a node. If the number of antinodes in wire \(A\) is \(p\) and that in \(B\) is \(q\) then the ratio \(p : q\) is
- A \(1 : 4\)
- B \(1 : 2\)
- C \(3 : 5\)
- D \(4 : 9\)
Answer & Solution
Correct Answer
(B) \(1 : 2\)
Step-by-step Solution
Detailed explanation
Let mass per unit length of wires are \(\mu_{1}\) and \(\mu_{2}\) respectively. \(\because\) Materials are same, so density \(\rho\) is same. \(\mu_{1}=\frac{\rho \pi r^{2} L}{L}=\mu \text { and } \mu_{2}=\frac{\rho 4 \pi r^{2} L}{L}=4 \mu\) Tension in both are same…
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