JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
A batsman hits back a ball of mass \(0.4 \; kg\) straight in the direction of the bowler without changing its initial speed of \(15 \; ms ^{-1}\). The impulse imparted to the ball is \(\dots \; Ns\)
- A \(12\)
- B \(22\)
- C \(32\)
- D \(42\)
Answer & Solution
Correct Answer
(A) \(12\)
Step-by-step Solution
Detailed explanation
Impulse \(=\) change in momentum \(= m [ v -(- v )]=2 \; mv\) \(=2 \times 0.4 \times 15=12 \; Ns\)
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