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JEE Mains · Physics · STD 12 - Moving charges and magnetism
  • JEE Mains 2024
  • Hard
  • Numerical

In the given figure an ammeter \(A\) consists of a \(240 \Omega\) coil connected in parallel to a \(10 \Omega\) shunt. The reading of the ammeter is _______ \(\mathrm{mA}\).

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Answer & Solution

Correct Answer

(B) \(160\)

Step-by-step Solution

Detailed explanation

\(\text { Req }\)

\(=140.4+\frac{240 \times 10}{240+10}\)

\(\text { Req }=140.4+\frac{2400}{250}\)

\(\text { Req. }=150 \Omega\)

\(\therefore\) Current in ammeter\(   =\frac{24}{150}\)

\(=160 \mathrm{~mA}\)

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