JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
In the given figure an ammeter \(A\) consists of a \(240 \Omega\) coil connected in parallel to a \(10 \Omega\) shunt. The reading of the ammeter is _______ \(\mathrm{mA}\).
- A \(150\)
- B \(160\)
- C \(170\)
- D \(180\)
Answer & Solution
Correct Answer
(B) \(160\)
Step-by-step Solution
Detailed explanation
\(\text { Req }\) \(=140.4+\frac{240 \times 10}{240+10}\) \(\text { Req }=140.4+\frac{2400}{250}\) \(\text { Req. }=150 \Omega\) \(\therefore\) Current in ammeter\( =\frac{24}{150}\) \(=160 \mathrm{~mA}\)
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