JEE Mains · Physics · STD 12 - Moving charges and magnetism
- JEE Mains 2024
- Hard
- Numerical
In the given figure an ammeter \(A\) consists of a \(240 \Omega\) coil connected in parallel to a \(10 \Omega\) shunt. The reading of the ammeter is _______ \(\mathrm{mA}\).

Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(160\)
Step-by-step Solution
Detailed explanation
\(\text { Req }\)
\(=140.4+\frac{240 \times 10}{240+10}\)
\(\text { Req }=140.4+\frac{2400}{250}\)
\(\text { Req. }=150 \Omega\)
\(\therefore\) Current in ammeter\( =\frac{24}{150}\)
\(=160 \mathrm{~mA}\)
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