JEE Mains · Physics · STD 11 - 2. motion in straight line
A paratrooper jumps from an aeroplane and opens a parachute after 2 s of free fall and starts deaccelerating with \(3 m / s ^2\). At 10 m height from ground, while descending with the help of parachute, the speed of paratrooper is \(5 m / s\). The initial height of the aeroplane is ___________m.
\(\left( g =10 m / s ^2\right)\)
- A 62.5
- B 92.5
- C 20
- D 82.5
Answer & Solution
Correct Answer
(B) 92.5
Step-by-step Solution
Detailed explanation
A to B \(x _1=\frac{1}{2} \times 10 \times 2^2=20 m\) \(V =0+10 \times 2\) B to C \(5^2=20^2-2(3) x_2\) \(x_2=\frac{375}{6}\) \(x_2=62.5\) C to D \(x _3=10 m\) \(H=x_1+x_2+x_3=92.5\)
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