JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
A uniform disc with mass \(M=4\,kg\) and radius \(R=\) \(10\,cm\) is mounted on a fixed horizontal axle as shown in figure. A block with mass \(m =2\,kg\) hangs from a massless cord that is wrapped around the rim of the disc. During the fall of the block, the cord does not slip and there is no friction at the axle. The tension in the cord is_______ \(N\) \(\left(\right.\) Take \(\left.g =10\,ms ^{-2}\right)\)
- A \(2\)
- B \(11\)
- C \(12\)
- D \(10\)
Answer & Solution
Correct Answer
(D) \(10\)
Step-by-step Solution
Detailed explanation
\(2 g-T=2 a\) ...........\((1)\) \(TR =\frac{ MR ^{2}}{2} \alpha\) ...........\((2)\) \(\alpha=\frac{ a }{ R }\) ..........\((3)\) \(T =2 a\) \(2 g - T =2 a\) \(T = g =10\,N\)
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