JEE Mains · Physics · STD 11 - Newtons laws of motion
- JEE Mains 2024
- Hard
- MCQ
A simple pendulum of length \(1 \mathrm{~m}\) has a wooden bob of mass \(1 \mathrm{~kg}\). It is struck by a bullet of mass \(10^{-2} \mathrm{~kg}\) moving with a speed of \(2 \times 10^2 \mathrm{~ms}^{-1}\). The bullet gets embedded into the bob. The height to which the bob rises before swinging back is _______. (use \(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\) )
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(0.20 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{mu}=(\mathrm{M}+\mathrm{m}) \mathrm{V}\)
\(10^{-2} \times 2 \times 10^2 \cong 1 \times \mathrm{V}\)
\(\mathrm{V} \cong 2 \mathrm{~m} / \mathrm{s}\)
\(\mathrm{h}=\frac{\mathrm{V}^2}{2 \mathrm{~g}}=0.2 \mathrm{~m}\)
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