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JEE Mains · Physics · STD 12 - Electromagnetic waves
  • JEE Mains 2019
  • Medium
  • MCQ

A plane electromagnetic wave having a frequency \(n = 23.9\, GHz\) propagates along the positive \(z-\) direction in free space. The peak value of the electric field is \(60\, V/m\). Which among the following is the acceptable magnetic field component in the electromagnetic wave?

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Verified Solution

Answer & Solution

Correct Answer

(C) \(\vec B = 2 \times {10^{ - 7}}\,\sin \,\left( {0.5 \times {{10}^3}z - 1.5 \times {{10}^{11}}t} \right)\hat i\)

Step-by-step Solution

Detailed explanation

Magnetic field when electromagnetic wave propagates in \(+z\) direction.

\(\mathrm{B}=\mathrm{B}_{0} \sin (\mathrm{kz}-\omega \mathrm{t})\)

where

\(\mathrm{B}_{0}-\frac{60}{3 \times 10^{8}}=2 \times 10^{-7}\)

\(\mathrm{k}=\frac{2 \pi}{\lambda}=0.5 \times 10^{3}\)

\(\omega=2 \pi \mathrm{f}=1.5 \times 10^{11}\)

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