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JEE Mains · Physics · STD 11 - 5. work,energy,power and collision

A particle is moving in a circle of radius \(r\) under the action of a force \(F\, = \alpha r^2\) which is directed towards centre of the circle. Total mechanical energy (kinetic energy + potential energy) of the particle is (take potential energy \(= 0\) for \(r\, = 0\))

  1. A \(\frac{1}{2}\alpha {r^3}\)
  2. B \(\frac{5}{6}\alpha {r^3}\)
  3. C \(\frac{4}{3}\alpha {r^3}\)
  4. D \(\alpha {r^3}\)
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Answer & Solution

Correct Answer

(B) \(\frac{5}{6}\alpha {r^3}\)

Step-by-step Solution

Detailed explanation

As we Known, \(dU = F.dr\)…
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