JEE Mains · Physics · STD 12 - Dual nature of radiation and matter
- JEE Mains 2025
- Easy
- MCQ
In photoelectric effect, the stopping potential \(\left(\mathrm{V}_0\right) \mathrm{v} / \mathrm{s}\) frequency \((\nu)\) curve is plotted.
( h is the Planck's constant and \(\phi_0\) is work function of metal )
(A) \(\mathrm{V}_0 \mathrm{v} / \mathrm{s} \nu\) is linear.
(B) The slope of \(\mathrm{V}_0 \mathrm{v} / \mathrm{s} \nu\) curve \(=\frac{\phi_0}{\mathrm{~h}}\)
(C) h constant is related to the slope of \(\mathrm{V}_0 \mathrm{v} / \mathrm{s} \nu\) line.
(D) The value of electric charge of electron is not required to determine \(h\) using the \(V_0 \mathrm{v} / \mathrm{s} \nu\) curve.
(E) The work function can be estimated without knowing the value of \(h\).
Choose the correct answer from the options given below :
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) (A), (C) and (E) only
Step-by-step Solution
Detailed explanation
\(\begin{aligned}
& \mathrm{hv}=\phi+\mathrm{KE}_{\max } \\
& \mathrm{KE}_{\max }=\mathrm{eV}_0 \\
& \mathrm{~V}_0=\frac{\mathrm{hv}-\phi}{\mathrm{e}}
\end{aligned}\)
(A) \(\mathrm{V}_0 \mathrm{v} / \mathrm{s} \mathrm{V}\) is linear correct
(B) Slope
\(\mathrm{v}_0=\left(\frac{\mathrm{h}}{\mathrm{e}}\right) \mathrm{v}-\frac{\phi}{\mathrm{e}} \text { Wrong }\)
Slope \(\frac{h}{e}\)
(C) Correct
(D) Incorrect
(E) Correct
& \mathrm{hv}=\phi+\mathrm{KE}_{\max } \\
& \mathrm{KE}_{\max }=\mathrm{eV}_0 \\
& \mathrm{~V}_0=\frac{\mathrm{hv}-\phi}{\mathrm{e}}
\end{aligned}\)
(A) \(\mathrm{V}_0 \mathrm{v} / \mathrm{s} \mathrm{V}\) is linear correct
(B) Slope
\(\mathrm{v}_0=\left(\frac{\mathrm{h}}{\mathrm{e}}\right) \mathrm{v}-\frac{\phi}{\mathrm{e}} \text { Wrong }\)
Slope \(\frac{h}{e}\)
(C) Correct
(D) Incorrect
(E) Correct
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