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JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter

In an experiment with photoelectric effect, the stopping potential,

  1. A increases with increase in the intensity of the incident light
  2. B decreases with increase in the intensity of the incident light
  3. C increases with increase in the wavelength of the incident light
  4. D is \(\left(\frac{1}{\mathrm{e}}\right)\) times the maximum kinetic energy of the emitted photoelectrons
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Answer & Solution

Correct Answer

(D) is \(\left(\frac{1}{\mathrm{e}}\right)\) times the maximum kinetic energy of the emitted photoelectrons

Step-by-step Solution

Detailed explanation

From Einstein photoelectric equation \(\frac{h c}{\lambda}=\phi+e V_S\) Maximum K.E. \(=(\mathrm{K})_{\max }=e V s\) So, \(V_S=\frac{(\mathrm{K})_{\max }}{e}\)
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