In an experiment with photoelectric effect, the stopping potential,

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(D) is \(\left(\frac{1}{\mathrm{e}}\right)\) times the maximum kinetic energy of the emitted photoelectrons

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Detailed explanation

From Einstein photoelectric equation
\(\frac{h c}{\lambda}=\phi+e V_S\)
Maximum K.E. \(=(\mathrm{K})_{\max }=e V s\)
So, \(V_S=\frac{(\mathrm{K})_{\max }}{e}\)

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